x^2-2x-1800=0

Solution for x^2-2x-1800=0 equation:

x^2-2x-1800=0

a = 1; b = -2; c = -1800;
Δ = b2-4ac
Δ = -22-4·1·(-1800)
Δ = 7204
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7204}=\sqrt{4*1801}=\sqrt{4}*\sqrt{1801}=2\sqrt{1801}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{1801}}{2*1}=\frac{2-2\sqrt{1801}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{1801}}{2*1}=\frac{2+2\sqrt{1801}}{2}
$